m^2-600m+50=0

Solution for m^2-600m+50=0 equation:

m^2-600m+50=0

a = 1; b = -600; c = +50;
Δ = b2-4ac
Δ = -6002-4·1·50
Δ = 359800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{359800}=\sqrt{100*3598}=\sqrt{100}*\sqrt{3598}=10\sqrt{3598}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-600)-10\sqrt{3598}}{2*1}=\frac{600-10\sqrt{3598}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-600)+10\sqrt{3598}}{2*1}=\frac{600+10\sqrt{3598}}{2}
$